answer:This problem can be solved in Python by using nested `for` loops. We iterate through each row, and for each row we iterate through each column. If we find a 0, we return the (row, column) indices as a tuple. In Python, indices are 0-based, so the first row and first column are row 0 and column 0, respectively.Here is an example of how you might implement this:```pythondef zero_in_matrix(matrix): # Ensure matrix is rectangular if not all(len(row) == len(matrix[0]) for row in matrix): return "Matrix is not rectangular." # Iterate through rows for i in range(len(matrix)): # Iterate through columns in current row for j in range(len(matrix[i])): if matrix[i][j] == 0: return (i, j) # If no 0 is found return "No 0 found in matrix."# Test the functionmatrix = [[1,2,3],[4,0,6],[7,8,9]]print(zero_in_matrix(matrix))```When you run this script, it outputs `(1, 1)`, because the first zero in the matrix is found in the second row's second column (`matrix[1][1] = 0`).Please note, this code assumes the input is a list of lists where all of the inner lists are of the same length (which constitutes a rectangular matrix). If this assumption is not valid, the matrix check at the beginning would give a `False` output. If no zero is found in the matrix, the script will output `No 0 found in matrix.`

answer:Here is a simple Python program that eliminates the repeating characters in a string:```pythondef remove_duplicates(input_str): result = [] for char in input_str: if char not in result: result.append(char) return ''.join(result)input_str = "aardvark"print("Input String: ", input_str)print("Result After Removing Duplicates: ", remove_duplicates(input_str))```In this approach, we create a new list where we append the characters from the original string after checking if the character is already in the list. If the character is not already in the list result, we append it. Finally we join the characters in the list without any spaces between them to get the string without any repeating characters.

answer:To create an embossed or 3D effect, you need to add shadows, highlights, and gradients in SVG. Here is an example of applying shadows using the "filter" element and "feGaussianBlur", "feSpecularLighting", "feComposite", "feBlend", and "feOffset".```svg<svg width="32" height="32" viewBox="0 0 32 32" fill="none" xmlns="http://www.w3.org/2000/svg"><defs> <filter id="innerShadow" x="-50%" y="-50%" width="200%" height="200%"> <feComponentTransfer in=SourceAlpha> <feFuncA type="table" tableValues="1 0" /> </feComponentTransfer> <feGaussianBlur stdDeviation="2" /> <feOffset dx="1" dy="1" result="offsetblur" /> <feFlood flood-color="black" result="color" /> <feComposite in2="offsetblur" operator="in" /> <feComposite in2="SourceAlpha" operator="in" /> <feMerge> <feMergeNode in="SourceGraphic" /> <feMergeNode /> </feMerge> </filter></defs><path d="M13 2C11.3431 2 10 3.34315 10 5V12.7908L11 13.7005V6H28V26H11V18.2395L10 19.1492V27C10 28.6569 11.3431 30 13 30H26C27.6569 30 29 28.6569 29 27V5C29 3.34315 27.6569 2 26 2H13Z" fill="#212121" filter="url(#innerShadow)"/>...............```You would apply this same filter attribute to the other 'path' elements to give them the same embossed effect. Note: You would replace the "....." with the rest of your SVG code. Remember you can play around with the filter properties and add more filters to achieve the exact effect that you want. SVG filters are quite powerful and versatile.Please keep in mind this is just one of many ways to give SVG elements a 3D look. You can also use gradients and multiple filters to achieve more complex effects.

answer:Here's an example of a custom function that uses a do-while loop in Python:```pythondef guess_number_game(target_number, max_attempts): attempt = 1 guess = None while attempt <= max_attempts: guess = int(input(f"Attempt {attempt}. Guess the number: ")) if guess == target_number: print("Congratulations, you guessed correctly!") break elif guess < target_number: print("Too low!") else: print("Too high!") attempt += 1 else: print(f"Sorry, you've reached the maximum attempts! The target number was {target_number}.")if __name__ == "__main__": target = 42 # Target number to guess max_tries = 5 # Maximum number of attempts guess_number_game(target, max_tries)```This function uses a do-while loop to prompt the user to guess a number until they reach the maximum number of attempts or correctly guess the target number. Keep in mind that Python does not have `do-while` loop as a built-in feature, so we use a normal `while` loop with a break when the condition should make us exit the loop.

answer:Assuming you have three tables - `books`, `reviews`, and `genres`, your query might look something like this:```SQLSELECT users.username, reviews.review, reviews.ratingFROM booksINNER JOIN reviews ON books.id = reviews.book_idINNER JOIN genres ON books.genre_id = genres.idWHERE genres.genre_name = 'this certain genre'AND books.publication_date > DATE_SUB(CURRENT_DATE, INTERVAL 5 YEAR);```Please replace `'this certain genre'` with the genre you are interested in.This query joins the books, reviews, and genres tables based on their appropriate ids. The Where clause filters the result set such that only the genre of your choice and books published within the last 5 years are considered. Note: This assumes `review` and `rating` are in the `reviews` table and `username` is in the `users` table. Additionally, the tables are linked in the way that `reviews` table has `book_id` and `user_id` columns and `books` table has `genre_id` column. Furthermore, it is assumed that `publication_date` is a column of `books` table to hold the publication date of each book. If your real situation is different, you may need to adjust the query accordingly.

answer:Here is a simple Java program that takes an input string and returns it in reverse order:```javapublic class Main { public static void main(String[] args) { String input = "hello"; String reversed = reverseString(input); System.out.println("Reversed string is: " + reversed); } public static String reverseString(String str) { String reversed = ""; for(int i = str.length() - 1; i >= 0; i--) { reversed = reversed + str.charAt(i); } return reversed; }}```This program contains a method called "reverseString" that loops through the characters in the input string in reverse order, from the last character to the first. It then concatenates each character to a new string called "reversed". By the time the loop finishes, "reversed" contains the characters of the input string in reverse order. The result is then printed on the console.