answer:Here is a simple Java program that calculates the sum of all Fibonacci numbers that are less than 1000:```javapublic class Main { public static void main(String[] args) { int a = 0; int b = 1; int sum = 0; while (a < 1000) { sum += a; int temp = a; a = b; b = temp + b; } System.out.println("Sum of Fibonacci numbers < 1000: " + sum); }}```In this program, variables `a` and `b` are used to generate the Fibonacci sequence. The `while` loop continues until `a` becomes 1000 or more, at which point it stops adding numbers to `sum`. Therefore, `sum` contains the sum of all Fibonacci numbers that are less than 1000. Please note that this program considers the Fibonacci sequence to start with 0 and 1 (0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ...).

answer:Here is the Python solution taking above requirements into consideration. This solution uses the `re` module for string handling, `string` module for checking types of characters and `collections` module for counting times each type of characters appears in a string.```pythonimport reimport stringimport collectionsdef extract_advanced_data(error_prone_str): normalized_str = re.sub(r'[;,]', ' ', error_prone_str) words_list = normalized_str.split() if all(word.isupper() for word in words_list): index_count = sum(1 for c in error_prone_str if ord(c) % 2 == 0) return {"uppercase": index_count} else: character_categories = { 'uppercase': 0, 'lowercase': 0, 'digits': 0, 'special_symbols': 0, 'whitespaces': 0, 'undefined': 0 } for c in error_prone_str: if c.isupper(): character_categories['uppercase'] += 1 elif c.islower(): character_categories['lowercase'] += 1 elif c.isdigit(): character_categories['digits'] += 1 elif c in string.whitespace: character_categories['whitespaces'] += 1 elif c in string.punctuation: character_categories['special_symbols'] += 1 else: character_categories['undefined'] += 1 return character_categories```Explanation:In this solution, the function first normalizes the input string by replacing commas and semicolons with spaces, then split that normalized string into a list of words.If all words are uppercase, the function counts the number of characters that their ASCII codes are even numbers and returns a dictionary that tells how many such characters.Otherwise, the function counts number of times each type of characters (uppercase alphabet characters, lowercase alphabet characters, digits, special symbols, whitespaces and undefined) appears in the string and returns a dictionary that tells how many times each type of characters appears.

answer:Here is a Python dictionary that stores a warning message for each item in the list:```pythonfruit_warnings = { 'apple': 'Warning: This apple may be sour!', 'orange': 'Warning: This orange is extremely juicy!', 'banana': 'Warning: This banana is very ripe!'}```You can tailor the warning messages to your needs. Now, if you access `fruit_warnings['apple']`, Python will return 'Warning: This apple may be sour!'.

answer:Here is a simple React component that takes an array of names, eliminates duplicates, sorts it alphabetically and then displays it.```jsximport React from 'react';class NameList extends React.Component { render() { const names = ['John', 'Alice', 'Bob', 'John']; // Remove duplicates and sort alphabetically const uniqueSortedNames = Array.from(new Set(names)).sort(); return ( <ul> {uniqueSortedNames.map((name, index) => <li key={index}>{name}</li>)} </ul> ); }}export default NameList;```Please note that it's recommended to avoid using the array index as a key in React if the order of items may change. This can negatively impact performance and may cause issues with component state. If each item in your data array has a unique id, you should use that instead. In this example, I used index as a key because names are unique and simple strings, and the array isn't changing order after it's been rendered.

answer:Here you need to find unique combinations of n consecutive letters and they should occur at least twice in the given string. You also need to handle scenarios where repetition might occur with overlapping sequences.As the question didn't specify programming language, here is an implementation in Python:```pythondef is_happy(s, n): dict = {} length = len(s) for i in range(length-n+1): seq = s[i:i+n] if seq in dict: dict[seq] += 1 else: dict[seq] = 1 for key in dict: if dict[key] < 2: return False return True```The function 'is_happy' takes a string 's' and a number 'n' as its input. It will return True, if all unique combinations of 'n' consecutive letters occur at least twice. Otherwise, if there is any combination that doesn't occur twice, 'is_happy' will return False.The for loop scans through the string 's', from the beginning to 'length-n+1'. This is because when 'i' is 'length-n+1', 's[i:i+n]' extracts 'n' characters from the string starting at the index 'i'. If 'i' would start at 'length-n+1', 's[i:i+n]' would extract less than 'n' characters, so we stop at 'length-n'.The combination 'seq' of 'n' consecutive characters is checked whether it already exists in the dictionary. If it does, increase the count of 'seq' by 1; otherwise, add 'seq' to the dictionary with a count of 1.After going through the entire string 's', we then check if every combination of 'n' characters occur at least twice. If they do, return True; otherwise, if there is any combination that doesn't occur twice, return False. This is the main logic for the function 'is_happy'.

answer:Here is a python solution for the above problem. It uses a custom sort function that extracts the numerical part of the strings (which are assumed to be at the start of the string in this example array) and sorts based on that.```pythondef sort_based_on_number(arr): # Define a custom sorting function that extracts the numeric part of each string def get_numeric_part(s): return int(''.join(filter(str.isdigit, s))) # Sort the array using the custom sorting function in descending order arr.sort(key=get_numeric_part, reverse=True) return arr# Test the function with the provided example arrayarr = ['55z', '22y', '33x', '66w', '44v']print(sort_based_on_number(arr))```Results:`['66w', '55z', '44v', '33x', '22y']`The `sort_based_on_number` function sorts an array of strings based on the numeric part of each string in descending order. The `get_numeric_part` helper function uses Python's built-in `filter` and `isdigit` functions to extract only the numeric characters from each string, which are then converted to an integer with `int`.The array is then sorted in reverse order (since we want descending order) using this numeric value as the key.