answer:The issue with your approach seems to stem from the usage of sklearn's `train_test_split()` function, which shuffles the data by default before splitting it. This causes the chronological arrangement of the dates to be lost.Here's an alternative approach. First, you must make sure your data is sorted in ascending order by date. Then, manually split the dataframe based on the percentages you want:```python# Assuming a pandas DataFrame "df" sorted by date in ascending ordertrain_size = int(0.2 * len(features_dataframe))train_dataframe = features_dataframe[:train_size]test_dataframe = features_dataframe[train_size:]```In the above code, `train_dataframe` contains the earliest 20% of the records and `test_dataframe` contains the remaining recent 80% of the records. This should meet your needs as described in your question.

answer:Your code is actually already in C++ and seems correct. You don't need to change anything to make it compatible with C++ as it contains C++ structures (std::vector, std::string etc.) and libraries or headers <algorithm>, <set>, <string> and <vector>.This function tend to generate all possible unique permutations of every suffix of a given string.One important thing to remember is that although the code is written in C++, it will only run if you have a C++ compiler installed on your system and you're running the command from the environment where the compiler can execute it.Also, to use this function in a C++ application, make sure to wrap it in a proper class or call it from the main(...) function then compile and run the .cpp file. Here's a quick example of usage:```c++int main() { string str = "abc"; vector<string> res = all_permutated_suffixes(str); // Printing the result for(auto s : res){ cout << s << endl; } return 0;}```

answer:For unauthorized users, you can directly use AWS Amplify `API` class for calling AWS API Gateway endpoints. As you allowed unauthenticated identities to access your API in AWS Cognito Identity Pool, will implicitly handle the role assignment for unauthenticated users in the request to the AWS API Gateway.Here is a simple example:```jsximport { API } from 'aws-amplify';API.get(apiName, path, myInit) .then(response => { // Add your code here }) .catch(error => { console.log(error.response); });````apiName` and `path` are strings that you define when the API is created and configured. `myInit` is an optional parameter. Here is how `myInit` could be defined using headers.```jsxlet myInit = { headers: {}, // OPTIONAL response: true, // OPTIONAL (return entire response object instead of response.data) queryStringParameters: { // OPTIONAL name: 'param', },}```By doing this, you're making a GET request here. But if you want to make POST or PUT requests, you can use `API.post()` or `API.put()` respectively. The other parameters (like headers) can be set based off of the AWS API Gateway's configuration.Remember to configure the AWS Amplify in your project. You can configure it automatically (by using the AWS Amplify CLI) or manually (by invoking `Amplify.configure()`).```jsximport Amplify from 'aws-amplify';Amplify.configure({ Auth: { // REQUIRED only for Federated Authentication - Amazon Cognito Identity Pool ID identityPoolId: 'XX-XXXX-X:XXXXXXXX-XXXX-1234-abcd-1234567890ab', // REQUIRED - Amazon Cognito Region region: 'XX-XXXX-X', // OPTIONAL - Amazon Cognito User Pool ID userPoolId: 'XX-XXXX-X_abcd1234', // OPTIONAL - Amazon Cognito Web Client ID (26-char alphanumeric string) userPoolWebClientId: 'a1b2c3d4e5f6g7h8i9j0k1l2m3', // OPTIONAL - Enforce user authentication prior to accessing AWS resources or not mandatorySignIn: false, // OPTIONAL - Configuration for cookie storage // Note: if the secure flag is set to true, then the cookie transmission requires a secure protocol cookieStorage: { // REQUIRED - Cookie domain (only required if cookieStorage is provided) domain: '.yourdomain.com', // OPTIONAL - Cookie path path: '/', // OPTIONAL - Cookie expiration in days expires: 365, // OPTIONAL - Cookie secure flag secure: true }, // OPTIONAL - customized storage object storage: MyStorage, // OPTIONAL - Manually set the authentication flow type. Default is 'USER_SRP_AUTH' authenticationFlowType: 'USER_PASSWORD_AUTH' }});```Note: Replace 'XX-XXXX-X:XXXXXXXX-XXXX-1234-abcd-1234567890ab', 'XX-XXXX-X', 'XX-XXXX-X_abcd1234', 'a1b2c3d4e5f6g7h8i9j0k1l2m3', and '.yourdomain.com' with your actual Cognito pool details and domain name. This is just a placeholder.

answer:SELECT "NHL Team(s)"FROM table_1205598_1WHERE "Media Market Ranking" = 7; This code will select the NHL team(s) from the row where the Media Market Ranking is 7. In this case, the output will be "Bruins".

answer:Given this problem, let's start by understanding the condition when the counts of global and local inversions are equal.Local inversions are a subset of global inversions which means all local inversions are global inversions but the reverse isn't always true. Therefore, count of global inversions is generally greater than or equal to the count of local inversions. The count of the two inversions will only be equal when each global inversion is also a local inversion. This will only be the case when the permutation `A` is almost sorted, with maximum one place displacement. This is because local inversions permit displacement by one position only.Based on this understanding, to solve this problem in a manner that adheres to the time constraint, you can track the maximum integer you've seen as you traverse the array. If you reach a point where the maximum number is more than two positions away, it's guaranteed that there would be a global inversion which is not a local inversion, therefore you return `false`. If there is no such encounter, return `true`.Here's a Python solution that follows this approach:```pythondef isIdealPermutation(A): max_seen_so_far = -1 for i in range(len(A) - 2): max_seen_so_far = max(max_seen_so_far, A[i]) if max_seen_so_far > A[i + 2]: return False return True```In this solution, when `i` is at index `j`, `max_seen_so_far` is the maximum value from `A[0] to A[j]` and you keep checking if it's greater than `A[j+2]`. If at any point you find `max_seen_so_far` to be greater than `A[j+2]`, it means the permutation isn't almost sorted and there would exist a global inversion which isn't local. Therefore it's safe to return `false` at that point. If no such point is found, it means the permutation is almost sorted and you return `true`.

answer:This problem is quite straightforward. You can create a tuple in Python and store it in the variable named "address". Let's say, the residential street designation is "Peachtree St" and its corresponding dwelling numeral is "721". Here is how to do this in Python:```pythonaddress = ("Peachtree St", "721")```In a tuple, you can store different types of data, like strings, integers, etc. Although in your problem, both pieces of information are strings. A tuple is defined by including the elements within parentheses "( )", separated by commas.You can access the elements of the tuple by their index. For example, if you want to obtain the street name and dwelling numeral, you can do:```pythonstreet_name = address[0]dwelling_numeral = address[1]print("Street Name:", street_name)print("Dwelling Numeral:", dwelling_numeral)```Please note that tuple indexes start at 0 for the first element.